Colourful Solutions > The covalent model > 5 and 6 electron domain systems

The Mad Science Lab

Higher-level only

Some molecules cannot be easily described using the octet rule, as they have more than four electron pairs around the central atom. This section explores the phenomenon of octet expansion.

Syllabus ref: S2.2.13

Structure 2.2.13 - Some atoms can form molecules in which they have an expanded octet of electrons. (HL)

  • Visually represent Lewis formulas for species with five and six electron domains around the central atom.
  • Deduce the electron domain geometry and the molecular geometry for these species using the VSEPR model.

Guidance

Tools and links

  • Structure 3.1 - How does the ability of some atoms to expand their octet relate to their position in the periodic table?

Octet expansion

The elements in period 3 of the periodic table can use available 'd' orbitals to increase the number of electrons that can be accomodated in the outer valence shell. This only occurs when covalent bonding takes place involving relatively electronegative elements, such as oxygen, fluorine and chlorine.

This increase in the valence shell electrons is known as 'octet expansion' and it gives rise to molecules that have more than four charge centres on the central atom.

Octet expansion can also occur in ions.

Molecules with octet expansion
Ions with octet expansion
PCl5, SF6, XeF4, XeF6
PCl6-, SF5+

Although the actual theory is not needed at IB level, it is useful to understand how orbital systems can exist with more than four charge centres. The central atom 'borrows' orbitals from the 3d level (see) and hybridizes them along with the 3s and 3p orbitals (see section 0.24 - Hybridization), to produce the number of orbitals required to share electrons with covalently bonded atoms. Thus, sp3d2 (six orbitals) can be used to make an octahedral system.


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Electronic shapes of five and six electron domain centres

There is no perfect shape that allows five regions of electron density to be equally separated from one another. The shape adopted is trigonal bipyramidal. This involves a trigonal plane with two axial regions at 90º (perpendicular) to the plane.

Trigonal bipyramidal shape
The electron regions repel as far as possible

Six regions of electronic charge can be accomodated into a perfect octahedral shape.

The name 'octahedral' seems strange at first sight, as the 'octa' suggests that there are eight regions. The name 'octahedral' actually means 'eight faces, or sides'. Each side is produced by joining the ends of three axes.

Octahedral shape
The electron regions repel as far as possible

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Five electron domain systems

Five charge centres must involve a minimum of 10 electrons. Group 15 elements have 5 outer (valence) electrons. When bonded to five atoms this makes a total of 10 electrons = five shared pair charge centres.

phosphorus(V) fluoride - PF5

Phosphorus (group 15) has 5 valence electrons. Each fluorine provides one electron, there are 5 fluorines therefore 5 electrons. Total electrons = 10 = 5 pairs. All pairs used for bonding therefore molecular shape = electronic orientation. Trigonal bipyramidal

For molecules, or ions, with five electron domains, but only four attached atoms, there are two possible positions for the lone pair of electrons. It could either be in the axial (top or bottom) position of the trigonal pyramid, or it could be on one of the equatorial positions.

The disadvantage of an axial position is that this leaves the lone pair at 90º to three bonding pairs, whereas if an equatorial position is adopted, it leaves the lone pair at 90º to only two other bonding pairs. This second alternative is the lowest energy in terms of repulsion and therefore the one adopted.

sulfur(IV) fluoride - SF4

Sulfur (group 16) has 6 valence electrons. Each fluorine provides one electron, there are 4 fluorines therefore 4 electrons. Total electrons = 10 = 5 pairs, therefore electronically the pairs adopt a trigonal bipyramidal orientation. However, only four pairs are used for bonding, therefore molecular shape: sawhorse


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Six charge centre systems

Six charge centres adopt an octahedral orientation and when all six electron pairs are used for bonding it gives rise to an octahedral molecule, for example, SF6.

sulfur(IV) fluoride - SF4

Sulfur (group 16) has 6 valence electrons. Each fluorine provides one electron, there are 6 fluorines therefore 6 electrons. Total electrons = 12 = 6 pairs, therefore electronically the pairs adopt an octahedral orientation. All six pairs are used for bonding, therefore molecular shape: octahedral

When five bonding pairs are involved, there is no specific advantage, or disadvantage, for the lone pair as regards the position it adopts as the octahedral shape is totally symmetrical, however when only four pairs of electrons are used for bonding the two remaining lone pairs arrange themselves at 180º to one another.

This leaves the remaining bonding pairs in a square planar shape, for example XeF4.

Xenon tetrafluoride - XeF4

Xenon (group 18) has 8 valence electrons. Each fluorine atom provides 1 electron, there are 4 fluorines, therefore 4 more electrons. Total electrons = 12 = 6 pairs, therefore electronically, the pairs adopt a octahedral arrangement. Two of the electron pairs are not used for bonding. square planar


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Summary - determination of molecular shape

1. Count up the total valence electrons on the central atom. This is done by consideration of the group number of the central atom and the number of attached atoms.

2. The total number of electron pairs gives the electronic arrangement adopted:

3. Each of the atoms bonds to the central atom by means of a bonding pair of electrons. If there are no electron pairs remaining, then the molecular shape is the same as the electronic arrangement. If there are any lone pairs, then only the bonding pairs are considered in the molecular shape. The lone pairs may distort the final shape in some cases, due to greater repulsions between lone pairs and bonding pairs than between bonding pairs and bonding pairs.

Total electron pairs number of lone pairs electronic arrangement molecular shape
2 0 linear linear
3 0 trigonal planar trigonal planar
3 1 trigonal planar angular
4 0 tetrahedral tetrahedral
4 1 tetrahedral pyramidal
4 2 tetrahedral angular
5 0 trigonal bipyramidal trigonal bipyramidal
5 1 trigonal bipyramidal saw-horse
5 2 trigonal bipyramidal distorted T-shaped
5 3 trigonal bipyramidal linear
6 0 octahedral octahedral
6 1 octahedral umbrella
6 2 octahedral square planar

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Worked examples

Q223-01 Draw the Lewis structure, state the shape and predict the bond angles for the ICl4- species.

Answer


  • Iodine (group 17) is the central atom with 7 valence electrons
  • Each chlorine atom provides one electron = 4 electrons
  • 1 electron for the negative charge
  • Total electrons = 12 electrons = 6 pairs

The electronic structure is octahedral but only four of the sites are occupied. To minimise repulsion the axial sites take the lone pairs.

The final ionic shape is square planar, with bond angles Cl-Xe-Cl of 90º.



Q223-02 Draw and name the shape of the PCl6- ion:

Answer


  • Phosphorus (group 15) is the central atom with 5 valence electrons
  • Each chlorine atom provides one electron = 6 electrons
  • 1 electron for the negative charge (shown in green)
  • Total electrons = 12 electrons = 6 pairs

The electronic structure is octahedral with all six sites occupied.

The final ionic shape is octahedral.


Q223-03 What is the distribution of electron pairs and the arrangement of atoms in the triiodide ion, I3-?

Electron pairs
Atoms arrangement
A.
Tetrahedral
bent
B.
Square planar
linear
C.
Trigonal bipyramid
linear
D.
Trigonal bipyramid
bent

Answer


  • Iodine (group 17) is the central atom with 7 valence electrons
  • Each other iodine atom provides one electron = 2 electrons
  • 1 electron for the negative charge (shown in green)
  • Total electrons = 10 electrons = 5 pairs

The electronic structure is trigonal bipyramidal, with only two sites occupied. The occupied sites are both axial to minimise repulsions between the three pairs of equatorial electron pairs (the ion is shown on its side).


Q223-04 Which of the following contains a bond angle of 90º?

  1. I PCl4+
  2. II PCl5
  3. III PCl6-
  1. I and II only
  2. I and III only
  3. II and III only
  4. I, II and III

Answer


PCl4+ has (5 + 4 - 1 = 8 valence electrons) all are used for bonding with no lone pairs left over. Molecular shape = tetrahedral, bond angle 109º 28'.

PCl5 has (5 + 5 = 10 valence electrons) all are used for bonding with no lone pairs left over. Molecular shape = trigonal bipyramidal, bond angles 90º and 120º.

PCl6- has (5 + 6 + 1 = 12 valence electrons) all are used for bonding with no lone pairs left over. Molecular shape = octahedral, bond angles 90º.

Therefore correct response = II and III only


Q223-05 Draw a diagram that represents the correct geometry of the BrF5 molecule and state its shape.

Answer


  • Bromine (group 17) is the central atom with 7 valence electrons
  • Each fluorine atom provides one electron = 5 electrons
  • Total electrons = 12 electrons = 6 pairs

The electronic structure is octahedral, with only five sites occupied and one lone pair.

This distorts the remaining bonding pairs into an umbrella shape.


Q223-06 What is the smallest bond angle found in the PF5 molecule?

  1. 90º
  2. 109.5º
  3. 120º
  4. 180º

Answer


  • Phosphorus (group 15) is the central atom with 5 valence electrons
  • Each fluorine atom provides one electron = 5 electrons
  • Total electrons = 10 electrons = 5 pairs

All five sites occupied thereforethe electronic shape is the same as the molecular shape = trigonal bipyramidal, with bond angles of 120º and 90º.


Q223-07 Which molecule or ion does not have a tetrahedral shape?

  1. XeF4
  2. SiCl4
  3. BF4-
  4. NH4+

Answer


  • Xenon (group 18) is the central atom with 8 valence electrons
  • Each fluorine atom provides one electron = 4 electrons
  • Total electrons = 12 electrons = 6 pairs

Only four out of six sites are used for bonding, therefore the electronic shape is octahedral and the lone pairs occupy the axial positions to be as far apart as possible. The molecular shape is square planar, with bond angles of 90º.

All of the other molecules and ions are tetrahedral, therefore the correct response is XeF4


  Now test yourself

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